Time Problem Solving Rhetorical Essay Format

Justin can complete the project by himself in 6 hours, Jason can complete the project by himself in 9 hours, and Jacob can complete the project by himself in 8 hours.How long would it take the triplets to complete the project if they work together?How long would it take to paint the house if they worked together?Step 2: Solve the equation created in the first step.That means they together did 1/2 1/3 = 5/6th of the work.Remaining 1/6th of the work must be done by C, the only person present. In this article we learned, how to solve the time and work questions by applying the basic time and work formula and by using the unit’s approach.This can be done by first multiplying the entire problem by the common denominator and then solving the resulting equation. Click Here for Practice Problems Example 3 – One pipe can fill a swimming pool in 10 hours, while another pipe can empty the pool in 15 hours.

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That means Rita will be doing 3 – 2 = 1 unit per hour. First, we will calculate B’s 10 days work, which he did alone.Step 1: A problem involving work can be solved using the formula , where T = time working together, A = the time for person A working alone, and B = the time for person B working alone.In this case, one pipe is filling the pool and the other is emptying the pool so we get the equation: Step 2: Solve the equation created in the first step.Or You can take the total work to be equal to 120 units (the LCM of 24, 20 & 8).That implies A does 120/24 = 5 units a day, B does 120/20 = 6 units a day. Now if C does 4 units a day, he can finish the work in 120/4 = 30 days. If we add all this it will give us the work of 2A, 2B and 2C in 1 day i.e.In this case, there are three people so the equation becomes: Step 2: Solve the equation created in the first step.This can be done by first multiplying the entire problem by the common denominator and then solving the resulting equation. Or Besides that one more approach can be applied in the work and time questions i.e. Time and work short tricks can be applied in this case, as the numbers used are 8 hours & 12 hours, let the work be equal to 24 units (which is the LCM of 8 & 12).Now as they finish the work in 8 hours working together, that implies together they do 24/8 = 3 units an hour.Sol: The payment made to anybody is in the proportion of the work done and not in the ratio of days spent.Using work and time formula in 24 days working alone A & B would have done 24/48 = 1/2 and 24/72 = 1/3 of the work.

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