Solving Quadratic Word Problems

Just don't forget that when you solve a quadratic equation, you must have the equation set equal to 0.Therefore, we had to subtract 20 from both sides in order to have the equation set to 0.If so, study these "neat" examples carefully, until you are quite sure you follow the reasoning.Every once in a while, they'll get clever and put a "projectile" problem into a different environment.There is enough coverage on new additions to the syllabus with a significant amount of questions.The following animation is interactive: by clicking on the button, you can generate a random equation and its solutions appear at the same time.

Yes, this problem is a little trickier because the question is not asking for the maximum height (vertex) or the time it takes to reach the ground (zeros), instead it it asking for the time it takes to reach a height of 20 feet.

The frame will be cut out of a piece of steel, and to keep the weight down, the final area should be 28 cm when: x is about −9.3 or 0.8 The negative value of x make no sense, so the answer is: x = 0.8 cm (approx.) There are two speeds to think about: the speed the boat makes in the water, and the speed relative to the land: We can turn those speeds into times using: time = distance / speed (to travel 8 km at 4 km/h takes 8/4 = 2 hours, right?

) And we know the total time is 3 hours: total time = time upstream time downstream = 3 hours Put all that together: Two resistors are in parallel, like in this diagram: The total resistance has been measured at 2 Ohms, and one of the resistors is known to be 3 ohms more than the other. The formula to work out total resistance "R = 3 Ohms is the answer. Quadratic Equations are useful in many other areas: For a parabolic mirror, a reflecting telescope or a satellite dish, the shape is defined by a quadratic equation.

On this particular page, we are going to take a look at a physics "projectile problem". We know that the ball is going to shoot from the cannon, go into the air, and then fall to the ground. A ball is shot from a cannon into the air with an upward velocity of 40 ft/sec. Hopefully, you agree that we can use the quadratic formula to solve this equation.

Let's first take a minute to understand this problem and what it means. So, here's a mathematical picture that I see in my head. The equation that gives the height (h) of the ball at any time (t) is: h(t)= -16t Now, we've changed the question and we want to know how long did it take the ball to reach the ground. The problem didn't mention anything about a ground. I'm thinking that this may not be a factorable equation. The first time doesn't make sense because it's negative.

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