Solving Math Problems With Solutions Research Proposal Sociology

How many litres were milked from each cow each year?

Therefore the distance between stations B and C is 48 km. After two hours of driving she noticed that she covered 80 km and calculated that, if she continued driving at the same speed, she would end up been 15 minutes late. Since Susan covered 80 km in 2 hours, her speed was $V = \frac = 40$ km/hr.At the new production rate they made: \cdot 25 (x - 3)\cdot 30 = 75 30(x - 3)$ Therefore: x = 75 30(x -3) - 100$ x = 75 30x -90 - 100$ 0 -75 = 30x -25$ 5 = 5x$ $x = 23$ So the company worked 23 days and they made \cdot 25 100 = 675$ pieces.Problem 13 There are 24 students in a seventh grade class. Then the number of birches is - x$, and the number of boys is \times (24-x)$.$\frac\cdot x-\frac\cdot x=90$ $\frac\cdot x=90$ $x=270$So the book is 270 pages long.Problem 4A farming field can be ploughed by 6 tractors in 4 days.So 00 \frac\cdot x \frac \cdot (8100 - x) = 9100$ Therefore 00 \fracx \frac(8100 - x) = 9100$$\fracx = 190$$x = 3800$Therefore, the cows produced 38 litres of milk the first year, and 70$ and 30$ litres of milk the second year, respectively.Problem 10The distance between stations A and B is 148 km.Problem 1 A salesman sold twice as much pears in the afternoon than in the morning. Then Mary and Lucy picked x$ and $x 2$, respectively.If he sold 360 kilograms of pears that day, how many kilograms did he sell in the morning and how many in the afternoon? This must be equal to 360.x = 360$$x = \frac$$x = 120$ Therefore, the salesman sold 120 kg in the morning and \cdot 120 = 240$ kg in the afternoon. Together the three of them picked 26 kg of chestnuts. So $x 2x x 2=26$x=24$$x=6$ Therefore, Peter, Mary, and Lucy picked 6, 12, and 8 kg, respectively.b) By the time of the meeting at station C the freight train rode for $\frac \frac$ hours, i.e. Therefore it left station B at - (1 \frac) = 10 \frac$ hours, i.e. So she increased her speed by 10 km/hr and she arrived at city B 36 minutes earlier than she planned. If she continued at the same speed she would be $ minutes late, i.e. So, she covered the distance between A and B in \frac$ hr, and it was 36 min less than planned. When we equalize the expressions for the scheduled time, we get the equation: $\frac - \frac = 2 \frac \frac$ $\frac = \frac$ $\frac = \frac$ x - 50 = 4x 200$ $x = 250$ So, the distance between cities A and B is 250 km.the planned time on the road is $\frac - \frac$ hr. Problem 12To deliver an order on time, a company has to make 25 parts a day.

Leave a Reply

Your email address will not be published. Required fields are marked *

One thought on “Solving Math Problems With Solutions”