Solving For X Practice Problems
Given that the first time he took the test Brian had answered 150 questions correctly, how many correct answers did he answer in the second test?
If we use the method of addition in solving these two equations, we can see that what we get is a simplified equation in one variable, as shown below.There will be no change in the equation solving strategy and once you have learnt the above method, you do not need to bother about the coefficients at all.Next we present and try to solve the examples in a more detailed step-by-step approach. C 5x 2(x 7) = 14x – 7 5x 2x 14 = 14x – 7 7x 14 = 14x – 7 7x – 14x = -14 – 7 -7x = -21 x = 3 3. D 5x 3 = 7x – 1 now collect like terms 3 1 = 7x – 5x every time you move something it changes signs 4 = 2x anything multiplied is divided on the other side and vice versa 4/2 = x 2 = x 2. D The price increased from to () so the question is 5 is what percent of 20. You can review your answers and change them by checking the desired letter.Once you have finished, press "finish" and you get a table with your answers and the right answers to compare with. And that value is put into the second equation to solve for the two unknown values.The solution below will make the idea of Substitution clear. x y = 15 -----(2) (10 y) y = 15 10 2y = 15 2y = 15 – 10 = 5 y = 5/2 Putting this value of y into any of the two equations will give us the value of x.Let's try θ = 30°: sin(−30°) = −0.5 and −sin(30°) = −0.5 So it is true for θ = 30° Let's try θ = 90°: sin(−90°) = −1 and −sin(90°) = −1 So it is also true for θ = 90° Is it true for all values of θ? Click "Show Answer" underneath the problem to see the answer.